Diagonal Difference

Given a square matrix, calculate the absolute difference between the sums of its diagonals.

For example, the square matrix  is shown below:

1 2 3
4 5 6
9 8 9  

The left-to-right diagonal = . The right to left diagonal = . Their absolute difference is .

Function description

Complete the  function in the editor below.

diagonalDifference takes the following parameter:

• int arr[n][m]: an array of integers

Return

• int: the absolute diagonal difference

Input Format

The first line contains a single integer, , the number of rows and columns in the square matrix .
Each of the next  lines describes a row, , and consists of  space-separated integers .

Constraints

Output Format

Return the absolute difference between the sums of the matrix's two diagonals as a single integer.

Sample Input

3
11 2 4
4 5 6
10 8 -12

Sample Output

15

Explanation

The primary diagonal is:

11
   5
     -12

Sum across the primary diagonal: 11 + 5 - 12 = 4

The secondary diagonal is:

     4
   5
10

Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15

Note: |x| is the absolute value of x

SOLUTION:

#include<stdio.h>

#include<stdlib.h>

int main()

{

    int a[100][100],i,j,n,sum1=0,sum2=0;

    scanf("%d",&n);

    for(i=0;i<n;i++)

    {

        for(j=0;j<n;j++)

        {

            scanf("%d",&a[i][j]);

        }

    }

    for(i=0;i<n;i++)

    {

        for(j=0;j<n;j++)

        {

            if(i==j)

            {

                sum1=sum1+a[i][j];

            }

            

        }

    }

    for(j=0;j<n;j++)

    {

        for(i=n-1-j;i<n;i++)

        {

                    

                sum2=sum2+a[i][j];

            break;

        }

    }

    int diff=abs(sum1-sum2);

    printf("%d",diff);

    return 0;

}