Compare the Triplets

 Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

• If a[i] > b[i], then Alice is awarded 1 point.
• If a[i] < b[i], then Bob is awarded 1 point.
• If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

Example

a = [1, 2, 3]
b = [3, 2, 1]

• For elements *0*, Bob is awarded a point because a[0] .
• For the equal elements a[1] and b[1], no points are earned.
• Finally, for elements 2, a[2] > b[2] so Alice receives a point.

The return array is [1, 1] with Alice's score first and Bob's second.

Function Description

Complete the function compareTriplets in the editor below.

compareTriplets has the following parameter(s):

• int a[3]: Alice's challenge rating
• int b[3]: Bob's challenge rating

Return

• int[2]: Alice's score is in the first position, and Bob's score is in the second.

Input Format

The first line contains 3 space-separated integers, a[0], a[1], and a[2], the respective values in triplet a.
The second line contains 3 space-separated integers, b[0], b[1], and b[2], the respective values in triplet b.

Constraints

• 1 ≤ a[i] ≤ 100
• 1 ≤ b[i] ≤ 100

Sample Input 0

5 6 7
3 6 10

Sample Output 0

1 1

Explanation 0

In this example:

Now, let's compare each individual score:

• , so Alice receives  point.
• , so nobody receives a point.
• , so Bob receives  point.

Alice's comparison score is , and Bob's comparison score is . Thus, we return the array .

Sample Input 1

17 28 30
99 16 8

Sample Output 1

2 1

Explanation 1

Comparing the  elements,  so Bob receives a point.
Comparing the  and  elements,  and  so Alice receives two points.
The return array is .

SOLUTION:

#include <stdio.h>

int main()

{

    int alice[3],bob[3],result[2];

    int alice_res=0,bob_res=0;

    for(int i=0;i<3;i++)

        scanf("%d",&alice[i]);

    for(int i=0;i<3;i++)

        scanf("%d",&bob[i]);

    for(int i=0;i<3;i++)

    {

        if(alice[i]>bob[i])

           alice_res++;

        else if(alice[i]<bob[i])

          bob_res++;

        else {

            alice_res=alice_res;

            bob_res=bob_res;

        }

        

    }

    result[0]=alice_res;

    result[1]=bob_res;

    for(int i=0;i<2;i++)

    {

        printf("%d ",result[i]);

    }

    return 0;

}