Pattern Printing

 Print a pattern of numbers from to  as shown below. Each of the numbers is separated by a single space.

                            4 4 4 4 4 4 4  
                            4 3 3 3 3 3 4   
                            4 3 2 2 2 3 4   
                            4 3 2 1 2 3 4   
                            4 3 2 2 2 3 4   
                            4 3 3 3 3 3 4   
                            4 4 4 4 4 4 4   

Input Format

The input will contain a single integer .

Constraints

Sample Input 0

2

Sample Output 0

2 2 2
2 1 2
2 2 2

Sample Input 1

5

Sample Output 1

5 5 5 5 5 5 5 5 5 
5 4 4 4 4 4 4 4 5 
5 4 3 3 3 3 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 2 1 2 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 3 3 3 3 4 5 
5 4 4 4 4 4 4 4 5 
5 5 5 5 5 5 5 5 5

Sample Input 2

7

Sample Output 2

7 7 7 7 7 7 7 7 7 7 7 7 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 2 1 2 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 7 7 7 7 7 7 7 7 7 7 7 7 

SOLUTION:

#include <stdio.h>

int main() 

{

    int n,min;

    scanf("%d", &n);

    int len = n*2 - 1;

    for(int i=0;i<len;i++){

        for(int j=0;j<len;j++){

            if(i<j)

            {

                min=i;

            }

            else {

                min=j;

            }

            if(min<len-i)

            {

                min=min;

            }

            else {

                min=len-i-1;

            }

            if(min<len-j-1){

                min=min;

            }

            else {

                min=len-j-1;

            }

            

            printf("%d ", n-min);

        }

        printf("\n");

    }

    return 0;

}